Intermediate Algebra (12th Edition)

Published by Pearson
ISBN 10: 0321969359
ISBN 13: 978-0-32196-935-4

Chapter R - Section R.2 - Operations on Real Numbers - R.2 Exercises - Page 20: 48



Work Step by Step

The given expression, $ \dfrac{7}{5}-\left( \dfrac{9}{10}-\dfrac{3}{2} \right) ,$ simplifies to \begin{array}{l}\require{cancel} \dfrac{7}{5}-\left( \dfrac{9}{10}-\dfrac{15}{10} \right) \\\\= \dfrac{7}{5}-\left( \dfrac{9-15}{10} \right) \\\\= \dfrac{7}{5}-\left( \dfrac{-6}{10} \right) \\\\= \dfrac{7}{5}-\left( \dfrac{-3}{5} \right) \\\\= \dfrac{7}{5}+\dfrac{3}{5} \\\\= \dfrac{7+3}{5} \\\\= \dfrac{10}{5} \\\\= 2 .\end{array}
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