Intermediate Algebra (12th Edition)

Published by Pearson
ISBN 10: 0321969359
ISBN 13: 978-0-32196-935-4

Chapter R - Section R.2 - Operations on Real Numbers - R.2 Exercises - Page 20: 15

Answer

$-\frac{19}{12}$

Work Step by Step

$-\frac{7}{3}+\frac{3}{4}=-\frac{7\times4}{3\times4}+\frac{3\times3}{4\times3}=-\frac{28}{12}+\frac{9}{12}$ $\frac{9}{12}-\frac{28}{12}=\frac{9}{12}+(-\frac{28}{12})=\frac{9+(-28)}{12}=\frac{-19}{12}=-\frac{19}{12}$
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