Answer
$\frac{67}{30}$
Work Step by Step
$\frac{9}{10}-(-\frac{4}{3})=\frac{9}{10}+\frac{4}{3}=\frac{9\times3}{10\times3}+\frac{4\times10}{3\times10}=\frac{27}{30}+\frac{40}{30}=\frac{27+40}{30}=\frac{67}{30}$
Intermediate Algebra (12th Edition)
by Lial, Margaret L.; Hornsby, John; McGinnis, Terry
Published by
Pearson
ISBN 10:
0321969359
ISBN 13:
978-0-32196-935-4
Chapter R - Section R.2 - Operations on Real Numbers - R.2 Exercises - Page 20: 27
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