Answer
1.6335
Work Step by Step
We know that logarithms to base 10 are common logarithms, and $log_{10}x$ is equivalent to $log(x)$.
Therefore, $log(43)=log_{10}43$.
We know that for all positive numbers $a$ (where $a\ne1$), and all positive numbers $x$, $y=log_{a}x$ means the same as $x=a^{y}$.
Therefore, $log_{10}43\approx1.6335$, because $10^{1.6335}\approx43$.
