#### Answer

-11.4007

#### Work Step by Step

We know that logarithms with base $e$ are natural logarithms, and $ln(x)$ can be written as $log_{e}x$.
Therefore, $ln(e^{-11.4007})=log_{e}e^{-11.4007}$.
We know that for all positive numbers $a$ (where $a\ne1$), and all positive numbers $x$, $y=log_{a}x$ means the same as $x=a^{y}$.
Therefore, $log_{e}e^{-11.4007}=-11.4007$, because $e^{-11.4007}=e^{-11.4007}$.