Answer
-1.4724
Work Step by Step
We know that logarithms with base $e$ are natural logarithms, and $ln(x)$ can be written as $log_{e}x$.
Therefore, $ln(e^{-1.4724})=log_{e}e^{-1.4724}$.
We know that for all positive numbers $a$ (where $a\ne1$), and all positive numbers $x$, $y=log_{a}x$ means the same as $x=a^{y}$.
Therefore, $log_{e}e^{-1.4724}=-1.4724$, because $e^{-1.4724}=e^{-1.4724}$.