Answer
4.1506
Work Step by Step
We know that logarithms with base $e$ are natural logarithms, and $ln(x)$ can be written as $log_{e}x$.
Therefore, $ln(8.59\times e^{2})=log_{e}(8.59\times e^{2})$.
We know that for all positive numbers $a$ (where $a\ne1$), and all positive numbers $x$, $y=log_{a}x$ means the same as $x=a^{y}$.
Therefore, $log_{e}(8.59\times e^{2})\approx4.1506$, because $e^{4.1506}\approx e^{(8.59\times e^{2})}$.
