## Intermediate Algebra (12th Edition)

$x=\dfrac{2b\pm\sqrt{3a}}{5}$
$\bf{\text{Solution Outline:}}$ To find the solutions of the given equation, $(5x-2b)^2=3a ,$ take the square root of both sides ((Square Root Property). Then use the properties of equality to isolate $x.$ $\bf{\text{Solution Details:}}$ Taking the square root of both sides and then simplifying the radical, the equation above is equivalent to \begin{array}{l}\require{cancel} 5x-2b=\pm\sqrt{3a} .\end{array} Using the properties of equality to isolate $x$, the given equation is equivalent to \begin{array}{l}\require{cancel} 5x=2b\pm\sqrt{3a} \\\\ x=\dfrac{2b\pm\sqrt{3a}}{5} .\end{array}