Answer
Third Term: $9$
Factored Form: $(x+3)^2$
Work Step by Step
The third term, $c,$ of a perfect square trinomial is equal to the square of half the coefficient of the second term, $b$. That is,
\begin{align*}
c=\left(\dfrac{b}{2}\right)^2
.\end{align*}
Thus, in the given incomplete expression, $
x^2+6x+\overset{?}\_$, the missing third term, $c,$ that will make the trinomial a perfect square is
\begin{align*}
c&=\left(\dfrac{b}{2}\right)^2
\\\\&=
\left(\dfrac{6}{2}\right)^2
\\\\&=
\left(3\right)^2
\\&=
9
.\end{align*}
Taking the square roots of the first and second terms and following the sign of the middle term, the factored form of $
x^2+6x+9
,$ is $(x+3)^2$.