## Intermediate Algebra (12th Edition)

$x=\pm\sqrt{b}$
$\bf{\text{Solution Outline:}}$ To find the solutions of the given equation, $x^2-b=0 ,$ use the properties of equality to express the given equation in the form $x^2=c.$ Then take the square root of both sides (Square Root Property). $\bf{\text{Solution Details:}}$ Using the properties of equality, in the form $x^2=c,$ the given equation is equivalent to \begin{array}{l}\require{cancel} x^2=b .\end{array} Taking the square root of both sides (Square Root Property), the equation above is equivalent to \begin{array}{l}\require{cancel} x=\pm\sqrt{b} .\end{array}