## Intermediate Algebra (12th Edition)

$(z-5p)(z^2+5pz+25p^2)$
$\bf{\text{Solution Outline:}}$ To factor the given expression, $z^3-125p^3 ,$ use the factoring of the sum/difference of $2$ cubes. $\bf{\text{Solution Details:}}$ Using $(a\pm b)(a^2\mp ab+b^2)$ or the factoring of the sum/difference of $2$ cubes, the expression above is equivalent to \begin{array}{l}\require{cancel} (z-5p)[(z)^2+z(5p)+(5p)^2] \\\\= (z-5p)(z^2+5pz+25p^2) .\end{array}