# Chapter 5 - Section 5.3 - Special Factoring - 5.3 Exercises - Page 343: 17

$(4+x+3y)(4-x-3y)$

#### Work Step by Step

$\bf{\text{Solution Outline:}}$ To factor the given expression, $16-(x+3y)^2 ,$ use the factoring of the difference of $2$ squares. $\bf{\text{Solution Details:}}$ Using $a^2-b^2=(a+b)(a-b)$ or the factoring of the difference of $2$ squares, the factored form of the expression above is \begin{array}{l}\require{cancel} [4+(x+3y)][4-(x+3y)] \\\\= [4+x+3y][4-x-3y] \\\\= (4+x+3y)(4-x-3y) .\end{array}

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