## Intermediate Algebra (12th Edition)

$(p^2+16)(p+4)(p-4)$
$\bf{\text{Solution Outline:}}$ To factor the given expression, $p^4-256 ,$ use the factoring of the difference of $2$ squares twice. $\bf{\text{Solution Details:}}$ Using $a^2-b^2=(a+b)(a-b)$ or the factoring of the difference of $2$ squares, the factored form of the expression above is \begin{array}{l}\require{cancel} (p^2+16)(p^2-16) .\end{array} The last factor is also a difference of $2$ squares. Using the factoring of the difference of $2$ squares again, the expression above is equivalent to \begin{array}{l}\require{cancel} (p^2+16)(p+4)(p-4) .\end{array}