Intermediate Algebra (12th Edition)

Published by Pearson
ISBN 10: 0321969359
ISBN 13: 978-0-32196-935-4

Chapter 5 - Section 5.3 - Special Factoring - 5.3 Exercises - Page 343: 32

Answer

$5(4z-w)^2$

Work Step by Step

$\bf{\text{Solution Outline:}}$ To factor the given expression, $ 80z^2-40zq+5w^2 ,$ factor first the $GCF.$ Then, the resulting trinomial is a perfect square trinomial. Use the factoring of perfect square trinomials. $\bf{\text{Solution Details:}}$ Factoring the $GCF= 5 ,$ the given expression is equivalent to \begin{array}{l}\require{cancel} 5(16z^2-8zq+w^2) .\end{array} The trinomial above is a perfect square trinomial. Using $a^2\pm2ab+b^2=(a\pm b)^2,$ the expression above is equivalent to \begin{array}{l}\require{cancel} 5(4z-w)^2 .\end{array}
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