Answer
20
Work Step by Step
We are given that $f(x)=x^{2}-9$, $g(x)=2x$, and $h(x)=x-3$.
We know that $(fg)(x)=f(x)\times g(x)$.
Therefore, $(fg)(-2)=((-2)^{2}-9)\times(2(-2))=(4-9)\times(-4)=-5\times-4=20$.
Intermediate Algebra (12th Edition)
by Lial, Margaret L.; Hornsby, John; McGinnis, Terry
Published by
Pearson
ISBN 10:
0321969359
ISBN 13:
978-0-32196-935-4
Chapter 4 - Section 4.4 - Multiplying Polynomials - 4.4 Exercises - Page 306: 118
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