Answer
$2x^{3}-18x$
Work Step by Step
We are given that $f(x)=x^{2}-9$, $g(x)=2x$, and $h(x)=x-3$.
We know that $(fg)(x)=f(x)\times g(x)$.
Therefore, $(fg)(x)=(x^{2}-9)\times(2x)=x^{2}\times2x-9\times2x=2x^{2+1}-18x=2x^{3}-18x$.
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