Answer
16
Work Step by Step
We are given that $f(x)=x^{2}-9$, $g(x)=2x$, and $h(x)=x-3$.
We know that $(fh)(x)=f(x)\times h(x)$.
Therefore, $(fh)(1)=((1)^{2}-9)\times((1)-3)=(1-9)\times(1-3)=-8\times-2=16$.
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