Intermediate Algebra (12th Edition)

Published by Pearson
ISBN 10: 0321969359
ISBN 13: 978-0-32196-935-4

Chapter 4 - Section 4.4 - Multiplying Polynomials - 4.4 Exercises - Page 306: 105

Answer

$10x^{2}-2x$

Work Step by Step

We are given that $f(x)=2x$ and $g(x)=5x-1$. We know that $(fg)(x)=f(x)\times g(x)$. Therefore, $(fg)(x)=(2x)\times(5x-1)=2x\times5x+2x\times-1=10x^{1+1}+(-2x)=10x^{2}-2x=10x^{2}-2x$.
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