Answer
$$\left[ \begin {array}{cc} 0&0\\ 0&0
\end {array} \right]=(0)\left[ \begin {array}{cc} 2&-3\\ 4&1
\end {array} \right]+(0)\left[ \begin {array}{cc} 0&5\\ 1&-2
\end {array} \right].$$
Work Step by Step
Assume the combination
$$\left[ \begin {array}{cc} 0&0\\ 0&0
\end {array} \right]=a\left[ \begin {array}{cc} 2&-3\\ 4&1
\end {array} \right]+b\left[ \begin {array}{cc} 0&5\\ 1&-2
\end {array} \right].$$
We have the system
\begin{align*}
2a&=0\\
-3a+5b&=0\\
4a+b&=0\\
a-2b&=0.
\end{align*}
We get the solution $$a=0, \quad b=0.$$
Consequently,
$$\left[ \begin {array}{cc} 0&0\\ 0&0
\end {array} \right]=(0)\left[ \begin {array}{cc} 2&-3\\ 4&1
\end {array} \right]+(0)\left[ \begin {array}{cc} 0&5\\ 1&-2
\end {array} \right].$$
