Elementary Linear Algebra 7th Edition

Published by Cengage Learning
ISBN 10: 1-13311-087-8
ISBN 13: 978-1-13311-087-3

Chapter 4 - Vector Spaces - 4.4 Spanning Sets and Linear Independence - 4.4 Exercises - Page 178: 10

Answer

$S$ spans $R^2$.

Work Step by Step

Assume the combination $$a(1,-1)+b(2,1)=(0,0).$$ We have the system \begin{align*} a+2b&=0\\ -a+b&=0. \end{align*} Since the determinant of the matrix is given by $$\left| \begin{array} {cc} 1&2\\-1&1 \end{array} \right|=3\neq 0$$ then the system has unique solution, that is, $$a=0, \quad b=0.$$ Consequently, $S$ is linearly independent and since $R^2$ has the dimension $2$ then $S$ spans $R^2$.
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