Answer
$$w= 4u+6v
=(4,8,18,-2).$$
Work Step by Step
Let $u=(1,-1,0,,1)$, $v=(0,2,3,-1)$.
Since $\frac{1}{2}w=2u+3v$, then we have
$$w= 4u+6v=4(1,-1,0,1)+6(0,2,3,-1))
=(4,8,18,-2).$$
Elementary Linear Algebra 7th Edition
by Larson, Ron
Published by
Cengage Learning
ISBN 10:
1-13311-087-8
ISBN 13:
978-1-13311-087-3
Chapter 4 - Vector Spaces - 4.1 Vectors in Rn - 4.1 Exercises - Page 153: 35
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