## Elementary Linear Algebra 7th Edition

(a) $2v= (2,4,4)$ (b)$-v= (-1,-2,-2)$ (c) $\frac{1}{2}v= (\frac{1}{2},1,1)$
Let $v$ be given by $v=(1,2,2)$, now we have (a) $2v=2(1,2,2)=(2,4,4)$ (b)$-v=-(1,2,2)=(-1,-2,-2)$ (c) $\frac{1}{2}v=\frac{1}{2}(1,2,2)=(\frac{1}{2},1,1)$