Elementary Linear Algebra 7th Edition

Published by Cengage Learning
ISBN 10: 1-13311-087-8
ISBN 13: 978-1-13311-087-3

Chapter 4 - Vector Spaces - 4.1 Vectors in Rn - 4.1 Exercises - Page 153: 17

Answer

(a) $2 v=2(2,1)=(4,2) $ (b) $-3 v=-3(2,1)=(-6,-3)$ (c) $ \frac{1}{2} v=\frac{1}{2}(2,1)=\left(1, \frac{1}{2}\right)$

Work Step by Step

(a) $2 v=2(2,1)=(4,2) $ (b) $-3 v=-3(2,1)=(-6,-3)$ (c) $ \frac{1}{2} v=\frac{1}{2}(2,1)=\left(1, \frac{1}{2}\right)$
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