Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

Published by Pearson
ISBN 10: 0-32184-874-8
ISBN 13: 978-0-32184-874-1

Chapter R - Elementary Algebra Review - R.6 Rational Expressions and Equations - R.6 Exercise Set - Page 980: 8



Work Step by Step

We can remove a factor of : $\frac{a+1}{a+1}=1$ $\frac{a^3+2a^2+a}{a^2+4a+3}=\frac{a(a^2+2a+1)}{(a+1)(a+3)}=\frac{a(a+1)(a+1)}{(a+1)(a+3)}=\frac{a(a+1)}{a+3}$
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