Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

Published by Pearson
ISBN 10: 0-32184-874-8
ISBN 13: 978-0-32184-874-1

Chapter R - Elementary Algebra Review - R.6 Rational Expressions and Equations - R.6 Exercise Set - Page 980: 10

Answer

$-1$

Work Step by Step

We can remove a factor of : $\frac{n-3}{n-3}=1$ $\frac{n-3}{3-n}=\frac{n-3}{-(n-3)}=\frac{1}{-1}=-1$
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