Answer
$$z=79,\:x=17,\:y=9$$
Work Step by Step
Solving the system of equations using substitution, we find:
$$ \frac{3z+103}{20}+\frac{11+z}{10}+z=105 \\ z=79 \\ x=\frac{3\cdot \:79+103}{20}=17 \\ y=\frac{11+79}{10}=9$$
Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)
by Bittinger, Marvin L.; Ellenbogen, David J.; Johnson, Barbara L.
Published by
Pearson
ISBN 10:
0-32184-874-8
ISBN 13:
978-0-32184-874-1
Chapter 8 - Systems of Linear Equations and Problem Solving - 8.4 Systems of Equations in Three Variables - 8.4 Exercise Set - Page 538: 30
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