Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

Published by Pearson
ISBN 10: 0-32184-874-8
ISBN 13: 978-0-32184-874-1

Chapter 8 - Systems of Linear Equations and Problem Solving - 8.4 Systems of Equations in Three Variables - 8.4 Exercise Set - Page 538: 26



Work Step by Step

Solving the system of equations using substitution, we find: $$ 3\cdot \frac{7-6\left(-\frac{5z-1}{24}\right)-z}{10}-\frac{12}{5}\left(-\frac{5z-1}{24}\right)+\frac{2}{5}z=-1 \\ z=-3 \\ y=-\frac{5\left(-3\right)-1}{24}=\frac{2}{3} \\ x=\frac{7-6\cdot \frac{2}{3}-\left(-3\right)}{10}=.6$$
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