Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

Published by Pearson
ISBN 10: 0-32184-874-8
ISBN 13: 978-0-32184-874-1

Chapter 8 - Systems of Linear Equations and Problem Solving - 8.4 Systems of Equations in Three Variables - 8.4 Exercise Set - Page 538: 24

Answer

$$r=6,\:q=-1,\:p=-\frac{1}{2}$$

Work Step by Step

Solving the system of equations using substitution, we find: $$ 2\cdot \frac{3-\left(-\frac{-r+9}{3}\right)-r}{4}+2\left(-\frac{-r+9}{3}\right)-r=-9\\ r=6 \\ q=-\frac{-6+9}{3}\\ q=-1\\ p=\frac{3-\left(-1\right)-6}{4}\\ p=-\frac{1}{2}$$
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