Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

Published by Pearson
ISBN 10: 0-32184-874-8
ISBN 13: 978-0-32184-874-1

Chapter 8 - Systems of Linear Equations and Problem Solving - 8.4 Systems of Equations in Three Variables - 8.4 Exercise Set - Page 538: 28

Answer

$$r=-\frac{1}{2},\:q=\frac{1}{2},\:p=4$$

Work Step by Step

Solving the system of equations using substitution, we find: $$ \frac{11-2r}{3}-6\left(4+7r\right)=1 \\ r=-.5 \\ q=4+7\left(-\frac{1}{2}\right)=.5 \\ p=\frac{11-2\left(-\frac{1}{2}\right)}{3}=4$$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.