Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

Published by Pearson
ISBN 10: 0-32184-874-8
ISBN 13: 978-0-32184-874-1

Chapter 8 - Systems of Linear Equations and Problem Solving - 8.2 Solving by Substitution or Elimination - 8.2 Exercise Set - Page 517: 57



Work Step by Step

Solving the two equations using substitution, we find: $$ 2\cdot \frac{9+7b}{13}-8b=6\\ b=-\frac{2}{3}\\ a=\frac{9+7\left(-\frac{2}{3}\right)}{13}\\ a=\frac{1}{3}$$
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