Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

Published by Pearson
ISBN 10: 0-32184-874-8
ISBN 13: 978-0-32184-874-1

Chapter 8 - Systems of Linear Equations and Problem Solving - 8.2 Solving by Substitution or Elimination - 8.2 Exercise Set - Page 517: 34


$(\displaystyle \frac{10}{21},\frac{11}{14})$

Work Step by Step

If we multiply the first equation with $4$, the terms containing $y$ will be opposite in the additive sense. $12x+8y=12$ $9x-8y=-2$ Add the equations $ 21x=10\qquad$ ... and solve for $x$ $x=\displaystyle \frac{10}{21}$ Substitute into one of the initial equations: $3(\displaystyle \frac{10}{21})+2y=3$ $2y=3-\displaystyle \frac{30}{21}$ $2y=\displaystyle \frac{63-30}{21}$ $2y=\displaystyle \frac{33}{21}$ $2y=\displaystyle \frac{11}{7}$ $y=\displaystyle \frac{11}{14}$ Form an ordered pair $(x,y)$ as the solution to the system $(\displaystyle \frac{10}{21},\frac{11}{14})$
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