Answer
$(\displaystyle \frac{10}{21},\frac{11}{14})$
Work Step by Step
If we multiply the first equation with $4$,
the terms containing $y$ will be opposite in the additive sense.
$12x+8y=12$
$9x-8y=-2$
Add the equations
$ 21x=10\qquad$ ... and solve for $x$
$x=\displaystyle \frac{10}{21}$
Substitute into one of the initial equations:
$3(\displaystyle \frac{10}{21})+2y=3$
$2y=3-\displaystyle \frac{30}{21}$
$2y=\displaystyle \frac{63-30}{21}$
$2y=\displaystyle \frac{33}{21}$
$2y=\displaystyle \frac{11}{7}$
$y=\displaystyle \frac{11}{14}$
Form an ordered pair $(x,y)$ as the solution to the system
$(\displaystyle \frac{10}{21},\frac{11}{14})$
