Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

Published by Pearson
ISBN 10: 0-32184-874-8
ISBN 13: 978-0-32184-874-1

Chapter 8 - Systems of Linear Equations and Problem Solving - 8.2 Solving by Substitution or Elimination - 8.2 Exercise Set - Page 517: 48


$$x=\frac{1}{2}, y=-\frac{1}{2}$$

Work Step by Step

Solving the two equations using substitution, we find: $$ 7y-3\cdot \frac{7+9y}{5}=-5\\ y=-\frac{1}{2}\\ x=\frac{7+9\left(-\frac{1}{2}\right)}{5}\\ x=\frac{1}{2}$$
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