## Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

$$x=\frac{1}{2}, y=-\frac{1}{2}$$
Solving the two equations using substitution, we find: $$7y-3\cdot \frac{7+9y}{5}=-5\\ y=-\frac{1}{2}\\ x=\frac{7+9\left(-\frac{1}{2}\right)}{5}\\ x=\frac{1}{2}$$