Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

Published by Pearson
ISBN 10: 0-32184-874-8
ISBN 13: 978-0-32184-874-1

Chapter 8 - Systems of Linear Equations and Problem Solving - 8.2 Solving by Substitution or Elimination - 8.2 Exercise Set - Page 517: 49

Answer

$$y=6,\:x=30$$

Work Step by Step

Solving the two equations using substitution, we find: $$ 10y+\frac{306-y}{10}=90\\ y=6\\ x=\frac{306-6}{10}\\ x=30$$
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