## Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

$$90$$
When the problem asks for the least common multiple, it is asking us for the smallest value that, when divided by either expression given, will result in a whole number. Finding the least common multiple using factors as well as trial and error, we find: $$2\cdot \:3\cdot \:3\cdot \:5\\ 90$$