#### Answer

$x+2$

#### Work Step by Step

Adding the numerators and copying the denominator, the given expression, $
\dfrac{x^2}{x+5}+\dfrac{7x+10}{x+5}
,$ simplifies to
\begin{array}{l}\require{cancel}
\dfrac{x^2+7x+10}{x+5}
\\\\=
\dfrac{(x+5)(x+2)}{x+5}
\\\\=
\dfrac{(\cancel{x+5})(x+2)}{\cancel{x+5}}
\\\\=
x+2
.\end{array}