Answer
$\dfrac{(3a-7)(a-2)}{(a+6)(a-1)}$
Work Step by Step
Subtracting the numerators and copying the denominator, the given expression, $
\dfrac{3a^2+14}{a^2+5a-6}-\dfrac{13a}{a^2+5a-6}
,$ simplifies to
\begin{array}{l}\require{cancel}
\dfrac{3a^2+14-13a}{a^2+5a-6}
\\\\=
\dfrac{3a^2-13a+14}{a^2+5a-6}
\\\\=
\dfrac{(3a-7)(a-2)}{(a+6)(a-1)}
.\end{array}
