#### Answer

$\dfrac{2y+7}{2y}$

#### Work Step by Step

When subtracting two fractions with common denominators, we subtract the numerators and copy the denominator. Therefore, the given expression, $
\dfrac{3y+8}{2y}-\dfrac{y+1}{2y}
,$ simplifies to
\begin{array}{l}\require{cancel}
\dfrac{3y+8-(y+1)}{2y}
\\\\=
\dfrac{3y+8-y-1}{2y}
\\\\=
\dfrac{2y+7}{2y}
.\end{array}