## Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

$\dfrac{2y+7}{2y}$
When subtracting two fractions with common denominators, we subtract the numerators and copy the denominator. Therefore, the given expression, $\dfrac{3y+8}{2y}-\dfrac{y+1}{2y} ,$ simplifies to \begin{array}{l}\require{cancel} \dfrac{3y+8-(y+1)}{2y} \\\\= \dfrac{3y+8-y-1}{2y} \\\\= \dfrac{2y+7}{2y} .\end{array}