# Chapter 5 - Polynomials and Factoring - 5.7 Solving Quadratic Equations by Factoring - 5.7 Exercise Set: 7

$x=\{-1,8\}$

#### Work Step by Step

Equating each factor to zero (Zero Product Principle), then the solutions to the given equation, $(x+1)(x-8)=0 ,$ is \begin{array}{l} x+1=0 \\\\ x=-1 ,\\\\\text{OR}\\\\ x-8=0 \\\\ x=8 .\end{array} Hence, $x=\{-1,8\} .$

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