Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

Published by Pearson
ISBN 10: 0-32184-874-8
ISBN 13: 978-0-32184-874-1

Chapter 5 - Polynomials and Factoring - 5.7 Solving Quadratic Equations by Factoring - 5.7 Exercise Set: 17

Answer

$x=\left\{ -\dfrac{8}{3},0 \right\}$

Work Step by Step

Equating each factor to zero (Zero Product Principle), then the solutions to the equation, $ 6n(3n+8)=0 ,$ is \begin{array}{l}\require{cancel} 6n=0 \\\\ n=\dfrac{0}{6} \\\\ n=0 ,\\\\\text{OR}\\\\ 3n+8=0 \\\\ 3n=-8 \\\\ n=-\dfrac{8}{3} .\end{array} Hence, $ x=\left\{ -\dfrac{8}{3},0 \right\} .$
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