Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

Published by Pearson
ISBN 10: 0-32184-874-8
ISBN 13: 978-0-32184-874-1

Chapter 5 - Polynomials and Factoring - 5.7 Solving Quadratic Equations by Factoring - 5.7 Exercise Set: 23

Answer

$x=\left\{ -7,3 \right\}$

Work Step by Step

Factoring the given equation, $ x^2+4x-21=0 ,$ results to \begin{array}{l}\require{cancel} (x+7)(x-3)=0 .\end{array} Equating each factor to zero (Zero Product Principle), then the solutions to the equation, $ (x+7)(x-3)=0 ,$ is \begin{array}{l}\require{cancel} x+7=0 \\\\ x=-7 ,\\\\\text{OR}\\\\ x-3=0 \\\\ x=3 .\end{array} Hence, $ x=\left\{ -7,3 \right\} .$
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