Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

Published by Pearson
ISBN 10: 0-32184-874-8
ISBN 13: 978-0-32184-874-1

Chapter 5 - Polynomials and Factoring - 5.7 Solving Quadratic Equations by Factoring - 5.7 Exercise Set: 6

Answer

$x=\{-10,-3\}$

Work Step by Step

Equating each factor to zero (Zero Product Principle), then the solutions to the given equation, $ (x+3)(x+10)=0 ,$ is \begin{array}{l} x+3=0 \\\\ x=-3 ,\\\\\text{OR}\\\\ x+10=0 \\\\ x=-10 .\end{array} Hence, $ x=\{-10,-3\} .$
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