Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

Published by Pearson
ISBN 10: 0-32184-874-8
ISBN 13: 978-0-32184-874-1

Chapter 4 - Polynomials - Mid-Chapter Review - Mixed Review - Page 263: 9



Work Step by Step

Using the laws of exponents, the given expression, $ \left( \dfrac{2a^2}{3} \right)^{-3} $, is equivalent to \begin{array}{l}\require{cancel} \dfrac{2^{-3}a^{2(-3)}}{3^{-3}} \\\\= \dfrac{3^{3}a^{-6}}{2^{3}} \\\\= \dfrac{27}{8a^{6}} .\end{array}
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