Answer
$\dfrac{-8b}{3}$
Work Step by Step
Using the laws of exponents, the given expression, $
\dfrac{-48ab^7}{18ab^6}
$, is equivalent to
\begin{array}{l}\require{cancel}
\dfrac{\cancel{6}\cdot(-8)a^{1-1}b^{7-6}}{\cancel{6}\cdot3}
\\\\=
\dfrac{-8a^{0}b^{1}}{3}
\\\\=
\dfrac{-8b}{3}
.\end{array}
