Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

Published by Pearson
ISBN 10: 0-32184-874-8
ISBN 13: 978-0-32184-874-1

Chapter 4 - Polynomials - Mid-Chapter Review - Mixed Review - Page 263: 6



Work Step by Step

Using the laws of exponents, the given expression, $ \dfrac{-48ab^7}{18ab^6} $, is equivalent to \begin{array}{l}\require{cancel} \dfrac{\cancel{6}\cdot(-8)a^{1-1}b^{7-6}}{\cancel{6}\cdot3} \\\\= \dfrac{-8a^{0}b^{1}}{3} \\\\= \dfrac{-8b}{3} .\end{array}
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.