Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

Published by Pearson
ISBN 10: 0-32184-874-8
ISBN 13: 978-0-32184-874-1

Chapter 4 - Polynomials - Mid-Chapter Review - Mixed Review: 8

Answer

$\dfrac{a^{2}}{bc^{3}}$

Work Step by Step

Using the laws of exponents, the given expression, $ (a^{-2}bc^3)^{-1} $, is equivalent to \begin{array}{l}\require{cancel} a^{-2(-1)}b^{-1}c^{3(-1)} \\\\= a^{2}b^{-1}c^{-3} \\\\= \dfrac{a^{2}}{b^{1}c^{3}} \\\\= \dfrac{a^{2}}{bc^{3}} .\end{array}
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