Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

Published by Pearson
ISBN 10: 0-32184-874-8
ISBN 13: 978-0-32184-874-1

Chapter 4 - Polynomials - Mid-Chapter Review - Mixed Review - Page 263: 3



Work Step by Step

Using the laws of exponents, the given expression, $ (x^2y^5)^8 $, is equivalent to \begin{array}{l} x^{2(8)}y^{5(8)} \\\\= x^{16}y^{40} .\end{array}
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.