Answer
$0.04-r^2t^2$
Work Step by Step
Using $(a+b)(a-b)=a^2-b^2$ or the product of the sum and difference of like terms, the given expression, $
(rt+0.2)(-rt+0.2)
,$ simplifies to
\begin{array}{l}\require{cancel}
(0.2+rt)(0.2-rt)
\\\\=
(0.2)^2-(rt)^2
\\\\=
0.04-r^2t^2
.\end{array}