Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

Published by Pearson
ISBN 10: 0-32184-874-8
ISBN 13: 978-0-32184-874-1

Chapter 4 - Polynomials - 4.7 Polynomials in Several Variables - 4.7 Exercise Set: 39

Answer

$3x^3-x^2y+xy^2-3y^3$

Work Step by Step

Removing the grouping symbols and then combining like terms, the given expression, $ (x^3-y^3)-(-2x^3+x^2y-xy^2+2y^3) ,$ simplifies to \begin{array}{l}\require{cancel} x^3-y^3+2x^3-x^2y+xy^2-2y^3 \\\\= (x^3+2x^3)-x^2y+xy^2+(-y^3-2y^3) \\\\= 3x^3-x^2y+xy^2-3y^3 .\end{array}
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