## Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

Published by Pearson

# Chapter 4 - Polynomials - 4.7 Polynomials in Several Variables - 4.7 Exercise Set - Page 284: 39

#### Answer

$3x^3-x^2y+xy^2-3y^3$

#### Work Step by Step

Removing the grouping symbols and then combining like terms, the given expression, $(x^3-y^3)-(-2x^3+x^2y-xy^2+2y^3) ,$ simplifies to \begin{array}{l}\require{cancel} x^3-y^3+2x^3-x^2y+xy^2-2y^3 \\\\= (x^3+2x^3)-x^2y+xy^2+(-y^3-2y^3) \\\\= 3x^3-x^2y+xy^2-3y^3 .\end{array}

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