Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

Published by Pearson
ISBN 10: 0-32184-874-8
ISBN 13: 978-0-32184-874-1

Chapter 4 - Polynomials - 4.7 Polynomials in Several Variables - 4.7 Exercise Set: 51

Answer

$20r^2t^2-23rt+6$

Work Step by Step

Using $(a+b)(c+d)=ac+ad+bc+bd$ or the product of $2$ binomials, the given expression, $ (5rt-2)(4rt-3) ,$ simplifies to \begin{array}{l}\require{cancel} 5rt(4rt)+5rt(-3)-2(4rt)-2(-3) \\\\= 20r^2t^2-15rt-8rt+6 \\\\= 20r^2t^2-23rt+6 .\end{array}
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