Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

Published by Pearson
ISBN 10: 0-32184-874-8
ISBN 13: 978-0-32184-874-1

Chapter 4 - Polynomials - 4.7 Polynomials in Several Variables - 4.7 Exercise Set: 57

Answer

$0.01-p^2q^2$

Work Step by Step

Using $(a+b)(a-b)=a^2-b^2$ or the product of the sum and difference of like terms, the given expression, $ (pq+0.1)(-pq+0.1) ,$ simplifies to \begin{array}{l}\require{cancel} (0.1+pq)(0.1-pq) \\\\= (0.1)^2-(pq)^2 \\\\= 0.01-p^2q^2 .\end{array}
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