Answer
$0.01-p^2q^2$
Work Step by Step
Using $(a+b)(a-b)=a^2-b^2$ or the product of the sum and difference of like terms, the given expression, $
(pq+0.1)(-pq+0.1)
,$ simplifies to
\begin{array}{l}\require{cancel}
(0.1+pq)(0.1-pq)
\\\\=
(0.1)^2-(pq)^2
\\\\=
0.01-p^2q^2
.\end{array}