## Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

$\dfrac{4}{5}$
RECALL: (1) $a^0=1, a\ne 0$ (2) $a^{-m} = \dfrac{1}{a^m}$ (3) $a^1 = a$ Use the rules above to obtain: $5^0-5^{-1} \\=1 - \dfrac{1}{5^1} \\=1 - \dfrac{1}{5}$ Since $1=\frac{5}{5}$, the expression above simplifies to: $=\dfrac{5}{5} -\dfrac{1}{5} \\=\dfrac{5-1}{5} \\=\dfrac{4}{5}$